The OPAMP related objective questions are given in this post with answers.
1. A non inverting closed loop op amp circuit generally has a gain factor
A. Less than one
B. Greater than one
C. Of zero
D. Equal to one
Ans: B. For non inverting amplifier the gain is A = [1 + (Rf/Rin)]. So it will be always more than one
2. If ground is applied to the (+) terminal of an inverting op-amp, the (–) terminal will
A. Not need an input resistor
B. Be virtual ground
C. Have high reverse current
D. Not invert the signal
Ans: B. Other options are not suitable.
3. The closed-loop voltage gain of an inverting amplifier equal to
A. The ratio of the input resistance to feedback resistance
B. The open-loop voltage gain
C. The feedback resistance divided by the input resistance
D. The input resistance
Ans: C
a) Current controlled Current source
b) Current controlled voltage source
c) Voltage controlled voltage source
d) voltage controlled current source
Ans: C. The ideal Opamp output voltage is maintained constant. It is controlled by input voltage.
6. The ideal OP-AMP has the following characteristics.
a) Ri=∞ ,A=∞ ,R0=0
b) Ri=0 ,A=∞ ,R0=0
c) Ri=∞ ,A=∞ ,R0=∞
d) Ri=0 ,A=∞ ,R0=∞
Ans: A.
7.Calculate the cutoff frequency of a first-order low-pass filter for R1 = 2.5kΩ and C1 = 0.05μF
A. 1.273kHz
B. 12.73kHz
C. 127.3 kHz
D. 127.3 Hz
Ans: A.
Hint: low pass filter cut off frequency f = 1/(2Ï€RC)
8. How many op-amps are required to implement this equation
A. 2
B. 3
C. 4
D. 1
Ans:D. The output voltage of inverting amplifier is Vout = (-Rf/Rin)Vin. By keeping 1 inverting amplifier and three no of sources (V1, V2, V3) in series corresponding input resistors(R1, R2, R3), we can get this equation.
9. How many op-amps are required to implement this equation Vo = V1
A. 4
B. 3
C. 2
D. 1
Ans: D. The voltage follower which has one opamp has the output of Vo = Vin
10. An OPAMP has a slew rate of 5 V/μ S .The largest sine wave O/P voltage possible at a frequency of 1 MHZ is
A. 10 volts
B. 5 volts
C. 5/ volts
D. 5/2 volts
1. A non inverting closed loop op amp circuit generally has a gain factor
A. Less than one
B. Greater than one
C. Of zero
D. Equal to one
Ans: B. For non inverting amplifier the gain is A = [1 + (Rf/Rin)]. So it will be always more than one
2. If ground is applied to the (+) terminal of an inverting op-amp, the (–) terminal will
A. Not need an input resistor
B. Be virtual ground
C. Have high reverse current
D. Not invert the signal
Ans: B. Other options are not suitable.
3. The closed-loop voltage gain of an inverting amplifier equal to
A. The ratio of the input resistance to feedback resistance
B. The open-loop voltage gain
C. The feedback resistance divided by the input resistance
D. The input resistance
Ans: C
4. When a number of stages are connected in parallel, the overall gain is the product of the individual stage gains
A. True
B. False
Ans: B
5. An ideal OP-AMP is an idealA. True
B. False
Ans: B
a) Current controlled Current source
b) Current controlled voltage source
c) Voltage controlled voltage source
d) voltage controlled current source
Ans: C. The ideal Opamp output voltage is maintained constant. It is controlled by input voltage.
6. The ideal OP-AMP has the following characteristics.
a) Ri=∞ ,A=∞ ,R0=0
b) Ri=0 ,A=∞ ,R0=0
c) Ri=∞ ,A=∞ ,R0=∞
d) Ri=0 ,A=∞ ,R0=∞
Ans: A.
7.Calculate the cutoff frequency of a first-order low-pass filter for R1 = 2.5kΩ and C1 = 0.05μF
A. 1.273kHz
B. 12.73kHz
C. 127.3 kHz
D. 127.3 Hz
Ans: A.
Hint: low pass filter cut off frequency f = 1/(2Ï€RC)
8. How many op-amps are required to implement this equation
A. 2
B. 3
C. 4
D. 1
Ans:D. The output voltage of inverting amplifier is Vout = (-Rf/Rin)Vin. By keeping 1 inverting amplifier and three no of sources (V1, V2, V3) in series corresponding input resistors(R1, R2, R3), we can get this equation.
9. How many op-amps are required to implement this equation Vo = V1
A. 4
B. 3
C. 2
D. 1
Ans: D. The voltage follower which has one opamp has the output of Vo = Vin
10. An OPAMP has a slew rate of 5 V/μ S .The largest sine wave O/P voltage possible at a frequency of 1 MHZ is
A. 10 volts
B. 5 volts
C. 5/ volts
D. 5/2 volts
Ans: D
Hint: Slew rate is defined as the max. rate of change of output voltage. Its unit is V/ μS.
Time period = 1/f = 1/1MHz = 1μS
V= Vm. sin(ωt) = Vm. sin(2πf.t)
slew rate = dV/dt = d(Vm. sin(2Ï€f.t)/ dt=Vm. 2Ï€f. cost...
Hint: Slew rate is defined as the max. rate of change of output voltage. Its unit is V/
Time period = 1/f = 1/1MHz = 1μS
V= Vm. sin(ωt) = Vm. sin(2πf.t)
slew rate = dV/dt = d(Vm. sin(2Ï€f.t)/ dt=Vm. 2Ï€f. cost...
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